Another Solution to the four zeros problem
posted by
budunk
- June 30 2011 10:19:27 AM
It could also be solved:
(cos(0)+cos(0)+cos(0)+cos(0))!=24
or
00:00 = 24 in military time.
Reply by
budunk
- July 01 2011 02:51:47 PM
Also:
((e^0)+(e^0)+(e^0)+(e^0))!=24
Reply by
Caprico
- July 02 2011 12:11:28 AM
The first post is right, but I don't think you're allowed to use "e", as its not really a function... Its a proper number... Like pi...